Ask a New Question
Search
Questions and answers by
Henry2,
Answers (196)
lol heres the answer: 45°
volume means base times width times hight. that means you would multiply everything: 1 1/2 times 3/4 times 2. ur welcome!
football = 0.38 * 500 = 190 students. basketball = 0.27 * 500 = 135 students. 190 - 135 =
Vo = 25ft./s[Ao]. Xo = 25*cosA. Yo = 25*sinA. Y^2 = Yo^2 + 2g*h = 0. Yo^2 +(- 64)*4.7 = 0, Yo = 17.3 ft/s. = vert. component of initial velocity. a. Yo = 25*sinA = 17.3 ft/s. b. A = 43.8o = angle of her launch. h = Yo*t + 0.5g*t^2 = 17.3*0.5 + (-16)*0.5^2
See post: 3-1-19, 1:28PM.
P1(-8, -4), P2(-4, -3). m = (-3-(-4))/(-4-(-8)) = 1/4. Y = mx + b. -4 = (1/4)*(-8) +b, b = -2. = Y-int. Eq: Y = (1/4)x - 2. 0 = (1/4)x - 2. X = 8 = x-int.
has 2 Lbs. of flour. 2/5 for pizza. 3/10*3/5 = 9/50 for bread. 7/10*3/5 = 21/50 remaining. Weight = 21/50 * 2 = 42/50 = 0.84 Lbs.
Total distance = X meters. swims x/4 meters. cycles 3/5*3x/4 meters = 9x/20 meters. runs 2/5*3x/4 = 6x/20 = 3600 meters. 6x/20 = 3600. X = 12,000 meters.
2/5 + 1/2 = 4/10 + 5/10 = 9/10 of his time. 1 - 9/10 = 10/10 - 9/10 = 1/10 of his time talking with friends. T = 1/10 * 6 = 0.6 h = 36 min. talking with friends.
As = (W*h)*2 + (L*h)*2 + (L*W)*2 = surface area As = (8*2)*2 + (12*2)*2 + (12*8)*2 =
Y = x - 3. Y = 2 - 3 = -1. So the answer is C.
V^2 = Vo^2 + 2g*h = 0. Vo^2 + (-19.6)2.222*10^6 = 0, Vo^2 = 43.55*10^6, Vo = 6,599.3 m/s.
F = 1625N/m * 0.121m = 196.6 N. Work = F * d = 196.6 * 0.121 = 23.8 Joules.
M*g = 31 * 9.8 = 303.8 N. = Wt. of block. h = 24 * sin30 = 12 m. KE + F*d = PE. 3645.6 + F*d = 303.8 * 12 = 3645.6, F*d = 0. Therefore, there is no friction and no work done by friction.
M*g = 1.11 * 9.8 = 10.9 N. = Wt. of block. Fp = 10.9*sin 28 = 5.1 N. = Force parallel to incline. Fn = 10.9*cos28 = 9.6 N. = Normal force. u*Fn = Force of kinetic friction Fp - u*Fn = M*a. a = 0(constant velocity). 5.1 - u*Fn = 1.11*0, u*Fn = 5.1 N. =
5/12 * 4/12 = 5/12 * 1/3 = 5/36.
a/d = 7/13. a/130 = 7/13, a = 70. c/a = 5/14. c/70 = 5/14. c = 25 students in cooking club.
5/12 * 4/12 =
sqrt(2x) + 3 + 6 = 0. sqrt(2x) = -9, 2x =(-9)^2 = 81, X = 40.5. Check: sqrt(2*40.5) +3 +6 = 0.). sqrt(81) + 3 + 6 = 0, -9 + 9 = 0. Note: The sq. root of 81 = +9 or (-9). I chose (-9), because it satisfies the Eq. If these operations are legal, we have one
As = (h*W)2 + (L*W)2 + (L*h)2. As = (8*14)2 + (10*14)2 + (10*8)2 =
N25E. = 25o E. of N. opposite = S25W. = 25o W. of S.
cost = $X before tax and tip. x + 0.08x + 0.2(x+0.08x) = 54.32. 1.08x + 0.216x = 54.32, X = $41.91. The answer is D.
(8, 3), (x, y), m = 5. m = (y-3)/(x-8) = 5. cross-multiply: y-3 = 5(x-8).
50km/4Liters = 12.5 km/Liter. d = 12.5km/Liter * 20Liters =
Y = -3x^2 + 12x + 15. Vertex form: Y = a(x-h)^2 + k. a = -3. h = -B/2A = -12/-6 = 2. k = -3*2^2 + 12*2 + 15 = 27.
(0, 3), m = 4. Y = mx + b. 3 = 4*0 + b, b = 3. Eq: Y = 4x + 3.
(4, 5), m = 2. Y = mx + b. 5 = 2*4 + b, b = -3. Eq: Y = 2x - 3.
(4, 5), m = -1/2. Y = mx + b. 5 = (-1/2)4 + b, b = 7. Eq: Y = (-1/2)x + 7.
F(x)-g(x) = x^2 + 2x - 6 - (x + 5) = x^2 + x - 11. Use Quad. Formula: X = 2.85, and -3.85.
Correction: a. d = -99 - 14i = 100 km. b. A = 82o W. of S. = 262o CW from +y-axis.
a. d = 80km[225] - 60km[135o]. X = 80*sin225 - 60*sin135 = -99 km. Y = 80*Cos225 - 60*Cos135 = -14 km. d = sqrt(X^2 + Y^2) = 100 km. b. Tan A = X/Y. A = 82o W of S. = 262o CW from +y-axis(bearing).
29*180/6 = 870o = 150o CCW. sin150 = sin30 = 1/2.
Correction: disregard my response to part b; I agree with bob' s answer.
a. Growth factor = 100% + 23% = 123% = 1.23. Bacteria = 180 *1.23^8 = 943. b. Value = 226,000 - 0.03*226,000*5 = $192,100.
D = M/V = M/L*W*h. D = 1050/LW*0.2 = 8.4 5,250/LW = 8.4, LW = 625 cm^2. L = W = sqrt(625) = 25 cm. 62
r = 245/3.5 = km/h. t = 90min. = 1.5 h. d = r * t =
a. d = 21[32] + 45[287]. X = 21*sin32 + 45*sin287 = -31.9km. Y = 21*Cos32 + 45*Cos287 = 30.97km. d = sqrt(X^2 + Y^2) = 44.46 km. b. Tan A = X/Y A = -45.8o = 314.2o CW from +y axis.
Yes, that is correct.
Po(1+r)^n = 100,000. r = 0.08/12 = 0.00666667 = monthly % rate. n = 1comp./mo * 120mo, = 120 compounding periods. Po(1.00666667)^120 = 100,000. Po = $45,052.33 = initial dep. Po(1+r)^10 = 100,000. Po(1.08)^10 = 100,000. Po = $46,319.35. 46,319.35 -
See previous post.
Vb = velocity of boat. Vc = velocity of current. Downstream: (Vb+Vc) * T = 110 mi. (Vb+Vc) * 5 = 110, Eq1: Vb+Vc = 22 mi/h. Upstream: (Vb-Vc) * T = 110. (Vb-Vc) * 7 6/7 = 110, Eq2: Vb - Vc = 14 mi/h. Add Eq1 and Eq2: Vb + Vc = 22. Vb - Vc = 14 Sum : 2Vb =
(x^5y^-3/5x^9)^-2. (x^-4y^-3/5)^-2, x^8y^6/5^-2, x^8y^6(5^2) = 25x^8y^6.
D1 = 1.22g/cm^3, T1 = 100oC. D2 = 0.95g/cm^3, T2 = 140oC. D3 = density @ 115oC. T.C. = (D2- D1)/(T2 - T1) = (0.95-1.22)/(140-100) = -0.00675/oC. = Temp. coefficient. D3 = D1 + (T.C.)*(T3-T1)D1 = 1.22 + (-0.00675)*(115-100) = 1.22 - 0.10125 = 1.11875
1. csc A = 4. 1/sinA = 4, sinA = 1/4 = Y/r, 2. x^2 + y^2 = 4^2. x^2 + 1^2 = 16, X = sqrt(15). Cos A = X/r = sqrt(15)/4. 3. Tan A = Y/X = 1/sqrt(15). 4. CSC A = r/Y = 4/1 = 4. 5. 6.
1. n^(3/2) = 125. Take cube root of both sides(raise to 1/3 power): n^(1/2) = 5, Sqrt(n) = 5, Square both sides: n = 25. check: 25^(3/2) = 25 * 25^(1/2) = 25 * sqrt(25) = 25 * 5 = 125.
V^2 = Vo^2 + 2a*d = 0. 40^2 + 2a*0.05 = 0, 1600 + 0.1a = 0, a = -16000 m/s^2. F = M*a = 0.3 * (-16,000) = -4800 N. The negative sign means the force opposes the mottion.
started with $X. x - 33 - 15 + 20 = 21.
scale: 1cm = 5ft. 1cm^2 = 25ft.^2. 1. A = 36cm^2 * 25ft^2/cm^2 = 900 sq. ft. 2. Ratio = 36/900 =
X = Larger number. Sqrt(x) + 19 = Smaller number. Eq1: x + sqrt(x)+19 = 151. sqrt(x) = 132 - x, Square both sides: x = 17,424-264x + x^2, x^2 -265x + 17,424 = 0. Use Quad. Formula. X = (-B +- sqrt(B^2-4AC))/2A. X = 144, and 121. 144 does not satisfy Eq1.
x + ( x+1) + (x+2) + (x+3) = t. 4x + 6 = t, 4x = t-6, X = (t-6)/4.
