Asked by Brady Kershner-Hanna
A spring with a force constant of 1625 N/m is compressed 12.1 cm. Find the work done by the force compressing the spring.
Answers
Answered by
bobpursley
work done=PE in spring= 1/2 k x^2
Answered by
Henry2,
F = 1625N/m * 0.121m = 196.6 N.
Work = F * d = 196.6 * 0.121 = 23.8 Joules.
Work = F * d = 196.6 * 0.121 = 23.8 Joules.
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