y=tanx -2π≤x≤2π y=cotx -2π≤x≤2π y=cscx

My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
1. 2 answers
2. asked by Jon
3. 983 views
Find a numerical value of one trigonometric function of x iftanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
1. 1 answer
2. asked by Lucy
3. 1,023 views
express this in sinx(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
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2. asked by linds
3. 1,459 views
For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
1. 5 answers
2. asked by CodyJinks
3. 815 views
How do I solve this? My work has led me to a dead end.tan(45-x) + cot(45-x) =4 my work: (tan45 - tanx)/(1+ tan45tanx) + (cot45 -
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2. asked by Jess
3. 796 views
(secx)/(tanx)+(cscx)/(cotx)=secx+cscxPlease help me verify this trigonometric identity.
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2. asked by Lainey
3. 647 views
(secx - tanx)(cscx+1) =cotx
1. 2 answers
2. asked by lizbeth
3. 539 views
tanx +cotx=secx cscx
1. 2 answers
2. asked by lizbeth
3. 551 views
y=tanx-2π≤x≤2π y=cotx -2π≤x≤2π y=cscx -2π≤x≤2π y=secx -2π≤x≤2π
1. 1 answer
2. asked by Reina Bonilla
3. 501 views
cotx+tanx=secx+cscx
1. 0 answers
2. asked by katie
3. 603 views