y=tanx -2π≤x≤2π y=cotx -2π≤x≤2π y=cscx

  1. My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
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    2. Jon asked by Jon
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  2. Find a numerical value of one trigonometric function of x iftanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
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    2. Lucy asked by Lucy
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  3. express this in sinx(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
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    2. linds asked by linds
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  4. For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
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    2. CodyJinks asked by CodyJinks
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  5. How do I solve this? My work has led me to a dead end.tan(45-x) + cot(45-x) =4 my work: (tan45 - tanx)/(1+ tan45tanx) + (cot45 -
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    2. Jess asked by Jess
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  6. (secx)/(tanx)+(cscx)/(cotx)=secx+cscxPlease help me verify this trigonometric identity.
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    2. Lainey asked by Lainey
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  7. (secx - tanx)(cscx+1) =cotx
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    2. lizbeth asked by lizbeth
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  8. tanx +cotx=secx cscx
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    2. lizbeth asked by lizbeth
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  9. y=tanx-2π≤x≤2π y=cotx -2π≤x≤2π y=cscx -2π≤x≤2π y=secx -2π≤x≤2π
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    2. Reina Bonilla asked by Reina Bonilla
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  10. cotx+tanx=secx+cscx
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    2. katie asked by katie
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