cotx+tanx=secx+cscx

cotx/secx-tanx

Prove (1+secx)/(tanx+sinx)=cscx

if cotx+tanx=a and secx-cosx=b then prove that (a^2b)^0.6667 -(ab^2)^0.6667=1

(secx)/(tanx)+(cscx)/(cotx)=secx+cscx Please help me verify this trigonometric identity.

(cotx)(cscx)+secx=(csc^2x)(secx) Please help to verify this trigonometric identity.

((cotx+cscx)/(sinx+tanx))=cotxcscx Please prove left side equal to right side, only doing doing w...

cscx+1/cscx cosx = secx+tanx

verify sinx/secx = 1/tanx+cotx

tanx +cotx=secx cscx

(secx - tanx)(cscx+1) =cotx

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