Asked by Potterhead
((cotx+cscx)/(sinx+tanx))=cotxcscx
Please prove left side equal to right side, only doing doing work on the left.
Please prove left side equal to right side, only doing doing work on the left.
Answers
Answered by
Reiny
LS = (cotx + cscx)/(sinx + tanx)
= (cosx/sinx + 1/sinx)/(sinx + sinx/cosx)
= ( (cox + 1)/sinx) / ( (sinxcosx + sinx)/cosx)
= (cosx + 1)/sinx * cox/(sinx(cosx + 1)
= cotx (cosx + 1)/(sinx(cosx + 1) )
= cotx (1/sinx)
= cotx cscx
= RS
= (cosx/sinx + 1/sinx)/(sinx + sinx/cosx)
= ( (cox + 1)/sinx) / ( (sinxcosx + sinx)/cosx)
= (cosx + 1)/sinx * cox/(sinx(cosx + 1)
= cotx (cosx + 1)/(sinx(cosx + 1) )
= cotx (1/sinx)
= cotx cscx
= RS
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