Asked by Marie

(cotx)(cscx)+secx=(csc^2x)(secx)

Please help to verify this trigonometric identity.

Answers

Answered by Steve
working with the left side,

cos/sin * 1/sin + 1/cos
cos/sin^2 + 1/cos
(cos^2+sin^2)/(sin^2 cos)
1/(sin^2 cos)
1/sin^2 * 1/cos
csc^2 sec
Answered by Marie
thank you!
Answered by Steve
you're welcome.

I always enjoyed doing trig identities. They provide endless variations. The hard ones for me, though, are the ones involving tan and sec combinations. They can get quite involved.
Answered by Tricia
cot^2 X - tan^2 X + sec^2 X = csc^2
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