Question

(cotx)(cscx)+secx=(csc^2x)(secx)

Please help to verify this trigonometric identity.

Answer 1

working with the left side,

cos/sin * 1/sin + 1/cos
cos/sin^2 + 1/cos
(cos^2+sin^2)/(sin^2 cos)
1/(sin^2 cos)
1/sin^2 * 1/cos
csc^2 sec

Answer 2

thank you!

Answer 3

you're welcome.

I always enjoyed doing trig identities. They provide endless variations. The hard ones for me, though, are the ones involving tan and sec combinations. They can get quite involved.

Answer 4

cot^2 X - tan^2 X + sec^2 X = csc^2