Asked by Marie
(cotx)(cscx)+secx=(csc^2x)(secx)
Please help to verify this trigonometric identity.
Please help to verify this trigonometric identity.
Answers
Answered by
Steve
working with the left side,
cos/sin * 1/sin + 1/cos
cos/sin^2 + 1/cos
(cos^2+sin^2)/(sin^2 cos)
1/(sin^2 cos)
1/sin^2 * 1/cos
csc^2 sec
cos/sin * 1/sin + 1/cos
cos/sin^2 + 1/cos
(cos^2+sin^2)/(sin^2 cos)
1/(sin^2 cos)
1/sin^2 * 1/cos
csc^2 sec
Answered by
Marie
thank you!
Answered by
Steve
you're welcome.
I always enjoyed doing trig identities. They provide endless variations. The hard ones for me, though, are the ones involving tan and sec combinations. They can get quite involved.
I always enjoyed doing trig identities. They provide endless variations. The hard ones for me, though, are the ones involving tan and sec combinations. They can get quite involved.
Answered by
Tricia
cot^2 X - tan^2 X + sec^2 X = csc^2
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