Question
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.
(x=theta BTW)
(x=theta BTW)
Answers
drwls
(secx/sinx)*(cotx/cscx)
= (secx/cscx)(cotx/sinx)
= (sinx/cosx)*cotx*(1/sinx)
The last steps should be obvious
= (secx/cscx)(cotx/sinx)
= (sinx/cosx)*cotx*(1/sinx)
The last steps should be obvious