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Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.

(x=theta BTW)
17 years ago

Answers

drwls
(secx/sinx)*(cotx/cscx)
= (secx/cscx)(cotx/sinx)
= (sinx/cosx)*cotx*(1/sinx)

The last steps should be obvious
17 years ago

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