I am not sure he is still here
(sinx/cosx)*cotx*(1/sinx)
(sin/cos)*(cos/sin) * (csc)
1 * (csc) = csc
remember csc = 1/sin
My previous question:
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.
(secx/sinx)*(cotx/cscx)
= (secx/cscx)(cotx/sinx)
= (sinx/cosx)*cotx*(1/sinx)
"The last steps should be obvious"
Not to me. I can convert (sinx/cosx) to tanx if that's even what I'm suppose to do. Is (sinx/cosx)*cotx*(1/sinx) the answer?
2 answers
I skipped that step that tanx*cotx = 1