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lim sqrt [(2+3x)/(1+5x)] x--->infinity I
Given f(x)=x^4(2x^2-15). On what interval(s) is the graph of f concave upwards?
A. (0, sqrt(3)) B. (-sqrt(3), 0) C. (-sqrt(3), 0)
1 answer
asked by
Sarah
929 views
When I solve the inquality 2x^2 - 6 < 0,
I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or
0 answers
asked by
Jen
1,298 views
lim x ->infinity (e^x/lnx)
I got infinity/0 but is that allowed to be my answer? what about this one: limx->infinity (sqrt of x
2 answers
asked by
Bob
520 views
find the domain of the real valued function;
f(x) = sqrt(5 - (sqrtx)) my solution: 5 - (sqrt x) >=0 -(sqrt x) >= -5 (sqrt x) <= 5
2 answers
asked by
HARRY
1,363 views
If f(x)=x-7 and g(x)=sqrt(4-x), what is the domain of the function f/g?
a. (-infinity, 4) b. (-infinity, 4] c. (4, infinity) d.
2 answers
asked by
Kathy
2,048 views
Evaluate the limit as x -> Infinity
[5x-sqrt(25x^2+4x)] Direct substitution yields the indeterminate form Infinity - Infinity.
6 answers
asked by
Sean
1,147 views
find lim f(x) - lim f(x)
x->infinity x->-infinity if f(x)=ln (x+sqrt[x^2+a^2])/(x+sqrt[x^2+b^2]) a and b are real numbers
0 answers
asked by
J
776 views
Consider the equation below. (Round the answers to three decimal places. If you need to use -infinity or infinity, enter
1 answer
asked by
Mike
847 views
lim t-> -infinity for sqrt(4t^2-5t-1)/(2t-3)
I get infinity or -infinity, but the real answer is -1. How does this occur?
1 answer
asked by
Joshua
560 views
Which of the following functions grows at the same rate as 3^x as x goes to infinity?
a)2^x b)sqrt(3^(x)+4) c)sqrt(6^x)
1 answer
asked by
Anonymous
4,773 views