dy/dx+2y=sinx, The answer is:1/5(2sinx+cosx)+cwith e

dy/dx+2y=sinx,The answer is:1/5(2sinx+cosx)+cwith e to the power (-2x)
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2. asked by shall
3. 427 views
dy/dx+2y=sinx,The answer is:1/5(2sinx+cosx)+cwith e to the power (-2x)
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2. asked by shalini
3. 429 views
How do you simplify:(1/(sin^2x-cos^2x))-(2/cosx-sinx)? I tried factoring and creating a LCD of (sinx+cosx)(sinx cosx)
1. 2 answers
2. asked by Shannon
3. 601 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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2. asked by shan
3. 992 views
hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
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2. asked by elle
3. 737 views
The equation 2sinx+sqrt(3)cotx=sinx is partially solved below.2sinx+sqrt(3)cotx=sinx sinx(2sinx+sqrt(3)cotx)=sinx(sinx)
1. 7 answers
2. asked by girly girl
3. 5,635 views
Which of the following are trigonometric identities?(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
1. 1 answer
2. asked by Jill
3. 4,817 views
Verify the identity:tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx
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2. asked by Ashley
3. 1,267 views
sin2x+cosx=0 , [-180,180)= 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in
1. 1 answer
2. asked by Anonymous
3. 938 views
solve each equation for 0=/<x=/<2pisin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
1. 7 answers
2. asked by sh
3. 962 views