Asked by Jill
Which of the following are trigonometric identities?
(Can be more then one answer)
tanx cosx cscx = 1
secx-cosx/secs=sin^2x
1-tanxtany=cos(x+y)/cosxcosy
4cosx sinx = 2cosx + 1 - 2sinx
Find all solutions to the equation cosx cos(3x) - sinx sin(3x) = 0 on the interval [0,2π]. (Points : 5)
π/8,3π/8,5π/8,7π/8,9π/8,11π/8,13π/8,15π/8
π/8,5π/8,9π/8,13π/8
3π/8,7π/8,11π/8,15π/8
π/8,9π/8, 15π/8
(Can be more then one answer)
tanx cosx cscx = 1
secx-cosx/secs=sin^2x
1-tanxtany=cos(x+y)/cosxcosy
4cosx sinx = 2cosx + 1 - 2sinx
Find all solutions to the equation cosx cos(3x) - sinx sin(3x) = 0 on the interval [0,2π]. (Points : 5)
π/8,3π/8,5π/8,7π/8,9π/8,11π/8,13π/8,15π/8
π/8,5π/8,9π/8,13π/8
3π/8,7π/8,11π/8,15π/8
π/8,9π/8, 15π/8
Answers
Answered by
Reiny
tanx cosx cscx
= sinx/cosx * cosx * 1/sinx
= 1
so the first one is an identity
For questions like this, I use this trick
pick a weird angle, e.g x = 13.79°
If that weird angle satisfies your equation, it is "highly likely" that it is an identify.
( I know that it does not prove it, but I would put a large sum of money on it)
2nd one works
3rd works
4th does not
cosx cos(3x) - sinx sin(3x0 = 0
You should recognize that pattern and get
cos(x+3x) = 0
cos (4x) = 0
4x = π/2 or 4x = 3π/2
x = π/8 or x = 3π/8
now the period of cos (4x) = 2π/4 or π/2
so by adding multiples of π/2 to any answer will give up new answers
π/8
π/8 + π/2 = 5π/8
5π/8 + π/2 = 9π/8
9π/8 + π/2 = 13π/8
etc. (numerator jumping by 4π)
same for 3π/8 , adding π/2 yields more answers
3π/8 , 7π/8, 11π/8 , 15π/8 , next one would be > 2π
looks like you answer #1, with 8 different answers.
= sinx/cosx * cosx * 1/sinx
= 1
so the first one is an identity
For questions like this, I use this trick
pick a weird angle, e.g x = 13.79°
If that weird angle satisfies your equation, it is "highly likely" that it is an identify.
( I know that it does not prove it, but I would put a large sum of money on it)
2nd one works
3rd works
4th does not
cosx cos(3x) - sinx sin(3x0 = 0
You should recognize that pattern and get
cos(x+3x) = 0
cos (4x) = 0
4x = π/2 or 4x = 3π/2
x = π/8 or x = 3π/8
now the period of cos (4x) = 2π/4 or π/2
so by adding multiples of π/2 to any answer will give up new answers
π/8
π/8 + π/2 = 5π/8
5π/8 + π/2 = 9π/8
9π/8 + π/2 = 13π/8
etc. (numerator jumping by 4π)
same for 3π/8 , adding π/2 yields more answers
3π/8 , 7π/8, 11π/8 , 15π/8 , next one would be > 2π
looks like you answer #1, with 8 different answers.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.