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Need help with current Trig problem for tomorrow:

Solve the logarithmic equation algebraically. Approximate the result to three decimal places.

6log3(0.5x)=11

I know to start off the equation you divide by 6.

I know the answer is 14.988. I just am puzzled on how to receive the answer.

1 answer

6log3(0.5x)=11
log3 (.5x) = 11/6

3^[log3 (.5x)] = .5 x = 3^(11/6)

x = 2 * 3^(11/6)

x = 2 * 4.494

x = 14.9882972

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