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dy/dx+2y=sinx,
The answer is:1/5(2sinx+cosx)+cwith e to the power (-2x)
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dy/dx+2y=sinx,
The answer is:1/5(2sinx+cosx)+cwith e to the power (-2x)
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How do you simplify:
(1/(sin^2x-cos^2x))-(2/cosx-sinx)? I tried factoring and creating a LCD of (sinx+cosx)(sinx cosx)
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tanx+secx=2cosx
(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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hey, i would really appreciate some help solving for x when:
sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
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