Asked by Ashley
Verify the identity:
tanx(cos2x) = sin2x - tanx
Left Side = (sinx/cosx)(2cos^2 x -1)
=sinx(2cos^2 x - 1)/cosx
Right Side = 2sinx cosx - sinx/cosx
=(2sinxcos^2 x - sinx)/cosx
=sinx(2cos^2 x -1)/cosx
= L.S.
Q.E.D.
tanx(cos2x) = sin2x - tanx
Left Side = (sinx/cosx)(2cos^2 x -1)
=sinx(2cos^2 x - 1)/cosx
Right Side = 2sinx cosx - sinx/cosx
=(2sinxcos^2 x - sinx)/cosx
=sinx(2cos^2 x -1)/cosx
= L.S.
Q.E.D.
Answers
There are no AI answers yet. The ability to request AI answers is coming soon!
There are no human answers yet. A form for humans to post answers is coming very soon!