Asked by ken
verify identity:
(tanx-cotx)/sinxcosx=sec^2x csc^2x
(tanx-cotx)/sinxcosx=sec^2x csc^2x
Answers
Answered by
Reiny
LS = (sinx/cosx - cosx/sinx)/(sinxcosx)
= [(sin^2x - cos^2x)/(sinxcosx)]/sinxcosx
= (sin^2x - cos^2x)/(sin^2x cos^2x)
=sin^2x/(sin^2xcos^2x) - cos^2x/(sin^2xcos^2x)
= 1/cos^2x - 1/sin^2x
= sec^2x - csc^2x
≠ RS
you have a typo, your right side should have been
sec^2x - csc^2x
= [(sin^2x - cos^2x)/(sinxcosx)]/sinxcosx
= (sin^2x - cos^2x)/(sin^2x cos^2x)
=sin^2x/(sin^2xcos^2x) - cos^2x/(sin^2xcos^2x)
= 1/cos^2x - 1/sin^2x
= sec^2x - csc^2x
≠ RS
you have a typo, your right side should have been
sec^2x - csc^2x
Answered by
shonne
what is the function of tan 7pi
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