Ask a New Question
Search
The Ka for the H2PO4–/HPO42–
The Ka for the H2PO4–/HPO42– buffer is given by the equation:
Ka= ([HPO4^-2]gamma [H^+])/[H2PO4^-]=10^-7.20 What is the pH of
1 answer
asked by
Cat
3,612 views
Phosphoric acid is a triprotic acid:
H3PO4(aq) +H2O(l) ↔ H3O+(aq) + H2PO4-(aq) Ka1 = 7.5 x 10-3 H2PO4-(aq) +H2O(l) ↔ H3O+(aq)
1 answer
asked by
Rachel
670 views
Phosphoric acid is a triprotic acid:
H3PO4(aq) +H2O(l) ↔ H3O+(aq) + H2PO4-(aq) Ka1 = 7.5 x 10-3 H2PO4-(aq) +H2O(l) ↔ H3O+(aq)
1 answer
asked by
Max
1,182 views
Given the table of Ka values on the right below, arrange the conjugate bases in order from strongest to weakest.
Acid Ka HClO 3.5
1 answer
asked by
linda
663 views
Assignment 1
Question Consider a monohydrogen phosphate ( HPO42-) and dihydrogen phosphate (H2PO4-) buffer solution. [HPO42-] =
1 answer
asked by
anonymous
1,248 views
For the reaction:
H2PO4- + HAsO42- ---> HPO42- + H2AsO4- Which pair exists as base in the equilibrium? H2PO4- & H2AsO4- are
0 answers
asked by
Swaastikaa
685 views
Give the formula for the conjugate base of each acid.
A.HSO4- B.H3PO4 C.HPO42- I have my answers as h2so4 h2po4 h2po4- my
1 answer
asked by
Danny
870 views
H2PO4-(aq)+OH-(aq) -> HPO42-(aq)+H2O
Experiment/[H2PO4-](M)/[OH-](M)/ Initial Rate(mol/L·min) 1 0.0031 0.00041 0.0021 2 0.0031
1 answer
asked by
Kat
1,024 views
How many milliliters of each solution of 0.50 M KH2PO4 and 0.50 M K₂HPO4 are needed to make 100.0 mL solution of phosphate
3 answers
asked by
James
216 views
h2po4(aq) + co34(aq) hco3 (aq) + hpo42 (aq)
1 answer
asked by
Adam
653 views