The Ka for the H2PO4–/HPO42–

The Ka for the H2PO4–/HPO42– buffer is given by the equation:Ka= ([HPO4^-2]gamma [H^+])/[H2PO4^-]=10^-7.20 What is the pH of
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2. asked by Cat
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Phosphoric acid is a triprotic acid:H3PO4(aq) +H2O(l) ↔ H3O+(aq) + H2PO4-(aq) Ka1 = 7.5 x 10-3 H2PO4-(aq) +H2O(l) ↔ H3O+(aq)
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2. asked by Rachel
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Phosphoric acid is a triprotic acid:H3PO4(aq) +H2O(l) ↔ H3O+(aq) + H2PO4-(aq) Ka1 = 7.5 x 10-3 H2PO4-(aq) +H2O(l) ↔ H3O+(aq)
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2. asked by Max
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Given the table of Ka values on the right below, arrange the conjugate bases in order from strongest to weakest.Acid Ka HClO 3.5
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2. asked by linda
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Assignment 1Question Consider a monohydrogen phosphate ( HPO42-) and dihydrogen phosphate (H2PO4-) buffer solution. [HPO42-] =
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For the reaction:H2PO4- + HAsO42- ---> HPO42- + H2AsO4- Which pair exists as base in the equilibrium? H2PO4- & H2AsO4- are
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2. asked by Swaastikaa
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Give the formula for the conjugate base of each acid.A.HSO4- B.H3PO4 C.HPO42- I have my answers as h2so4 h2po4 h2po4- my
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2. asked by Danny
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H2PO4-(aq)+OH-(aq) -> HPO42-(aq)+H2OExperiment/[H2PO4-](M)/[OH-](M)/ Initial Rate(mol/L·min) 1 0.0031 0.00041 0.0021 2 0.0031
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How many milliliters of each solution of 0.50 M KH2PO4 and 0.50 M K₂HPO4 are needed to make 100.0 mL solution of phosphate
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2. asked by James
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h2po4(aq) + co34(aq) hco3 (aq) + hpo42 (aq)
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2. asked by Adam
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