Asked by linda
Given the table of Ka values on the right below, arrange the conjugate bases in order from strongest to weakest.
Acid Ka
HClO 3.5 e-8
HClO2 1.2 e-2
HCN 6.2 e-10
H2PO4- 6.2 e-8
A. ClO2-, ClO¬-, HPO42-, CN-
B. ClO2-, HPO42-, ClO¬-, CN-
C. CN-, HPO42-, ClO-, ClO2¬-
D. CN-, ClO-, HPO42-, ClO2-
Acid Ka
HClO 3.5 e-8
HClO2 1.2 e-2
HCN 6.2 e-10
H2PO4- 6.2 e-8
A. ClO2-, ClO¬-, HPO42-, CN-
B. ClO2-, HPO42-, ClO¬-, CN-
C. CN-, HPO42-, ClO-, ClO2¬-
D. CN-, ClO-, HPO42-, ClO2-
Answers
Answered by
DrBob222
Kb = (Kw/Ka)
Calculate Kb for each acid, then arrange in order.
Calculate Kb for each acid, then arrange in order.
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