You must have. I ran through y (the exponent for OH^- and arrived at a value of 2. For x, the exponent of H2PO4^- I found 1.
For y, divide equation 2 by 1.
For x, divide equation 3 by 1.
If you can't find the error, post your work and I'll find it for you.
H2PO4-(aq)+OH-(aq) -> HPO42-(aq)+H2O
Experiment/[H2PO4-](M)/[OH-](M)/ Initial Rate(mol/L·min)
1 0.0031 0.00041 0.0021
2 0.0031 0.00082 0.0084
3 0.0093 0.00041 0.0063
4 ? 0.00034 0.0021
(second rows are moles of H2PO4, third rows are moles of OH, and the last rows are initial rate).
I am supposed to find the rate law, but I am having trouble. When I was trying to find x and y, the numbers were so bizarre. For x, it was 0.75 = 3^x and for y, it was 4 = 20^y. Did I do something wrong in the process? help me!
1 answer
1 answer