Consider the function f(t)=2sec^2(t)–6t^2 .

Could someone please help with this question.State the properties of y = 2sec(-2x + 180°) + 3. My answer: First I graphed y =
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2. asked by Matt
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Prove that the following Trigonometric Identity is valid:1/(sin⁡(y)-1)-1/(sin⁡(y)+1)=-2sec^2 (y) Please any help or clues on
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2. asked by kat
3. 556 views
Consider the function f(t)=2sec^2(t)–10t^3. Let F(t) be the antiderivative of f(t) with F(0)=0.Then F(2) my problem is i get
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2. asked by sonia
3. 488 views
Am I right on this?2sec^2(2x)-8=0 2sec^2(2x)=8 divide by 2 sec^2(2x)=4 find square root sec(2x)=2 Now, would this simply be
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2. asked by Alex
3. 462 views
Find the differential dy of the given function.y=sec^2x/(x^2+1) My answer was [tanx(x^2+1)-2sec^2x]dx/(x^2+1)^2 My friend (who's
1. 3 answers
2. asked by Lindsay
3. 578 views
Consider the function f(t)=2sec^2(t)–6t^2 . Let F(t) be the antiderivative of f(t) with F(0)=0 .Then F(5)=? I am confused on
1. 3 answers
2. asked by sam
3. 923 views
Given the function f with the restricted domain, find the points at which the tangent line is horizontal.f(x)=2sec(x)-tan(x)
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2. asked by Ashley
3. 529 views
cos x/1+sin x + 1+sin x/ cos x= 2sec x
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2. asked by val
3. 531 views
Sec^2(u/2)=(2sec(u))/(sec(u)+1)
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2. asked by Dax
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tan^2(x)=-3/2sec(x)
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2. asked by Blair
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