Asked by Dax
Sec^2(u/2)=(2sec(u))/(sec(u)+1)
Answers
Answered by
bobpursley
It would be helpful to know what you need with this identity. Prove it? One wonders.
If so, you need to start on another identity.
Remember cos(2x)=cos^2(x) - sin^2(x)=cos^2(x)-(1-cos^2(x))=2cos^2(x)-1 or
cos^2(x)=1/2 (1+cos(2x))
now replace 2x=u and you have
cos^2(u/2)=1/2 (1+cos(u))
and
sec^2(u/2)=2/(1+1/sec(u))
now multiply the right side by secu/secu
sec^2(u/2)=2sec(u)/(sec(u)+1)
viola.
If so, you need to start on another identity.
Remember cos(2x)=cos^2(x) - sin^2(x)=cos^2(x)-(1-cos^2(x))=2cos^2(x)-1 or
cos^2(x)=1/2 (1+cos(2x))
now replace 2x=u and you have
cos^2(u/2)=1/2 (1+cos(u))
and
sec^2(u/2)=2/(1+1/sec(u))
now multiply the right side by secu/secu
sec^2(u/2)=2sec(u)/(sec(u)+1)
viola.
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