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AgCl Ag^+ + Cl^- NaCl
AgCl <==> Ag^+ + Cl^-
NaCl ==> Na^+ + Cl^- Ksp = (Ag^+)(Cl^-) = 1.8 x 10^-10 Let S = solubility of AgCl, then (Ag^+) = S (Cl^-) =
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