Use the procedure in the succeeding problem [HNO3 and Ba(OH)2] to solve this one. Also you may need the stoichiometry procedure too. Here is the link again.
http://www.jiskha.com/science/chemistry/stoichiometry.html
NaCl(aq) + AgNO3(aq) โ AgCl(s) + NaNO3(aq)
http://www.jiskha.com/science/chemistry/stoichiometry.html
First, let's write the balanced chemical equation:
NaCl(aq) + AgNO3(aq) โ AgCl(s) + NaNO3(aq)
From the equation, we can see that the mole ratio between NaCl and AgNO3 is 1:1. This means that 1 mole of NaCl reacts with 1 mole of AgNO3.
To find the moles of NaCl, we can use the concentration and volume of the NaCl solution:
moles of NaCl = concentration ร volume
moles of NaCl = 0.278 M ร 47.1 mL
moles of NaCl = 0.01306 moles
Since the mole ratio between NaCl and AgNO3 is 1:1, we need the same number of moles of AgNO3 to react:
moles of AgNO3 = 0.01306 moles
Now, let's find the volume of the AgNO3 solution in milliliters needed to have 0.01306 moles of AgNO3.
volume of AgNO3 = moles of AgNO3 / concentration of AgNO3
volume of AgNO3 = 0.01306 moles / 0.277 M
volume of AgNO3 = 0.0471 L
Converting from liters to milliliters:
volume of AgNO3 = 0.0471 L ร 1000 mL/L
volume of AgNO3 = 47.1 mL
Therefore, 47.1 mL of 0.277 M AgNO3 solution is needed to react completely with 47.1 mL of 0.278 M NaCl solution.
Now, let's calculate the mass of AgCl formed.
From the stoichiometry of the balanced chemical equation, we can see that the mole ratio between AgNO3 and AgCl is 1:1. This means that 1 mole of AgNO3 produces 1 mole of AgCl.
moles of AgCl = moles of AgNO3
moles of AgCl = 0.01306 moles
To find the mass of AgCl, we can use the molar mass of AgCl:
mass of AgCl = moles of AgCl ร molar mass of AgCl
mass of AgCl = 0.01306 moles ร (107.87 g/mol)
mass of AgCl = 1.39 grams
Therefore, 1.39 grams of AgCl will be formed.
Step 1: Write the balanced equation for the reaction:
NaCl(aq) + AgNO3(aq) โ AgCl(s) + NaNO3(aq)
Step 2: Determine the mole ratio of AgNO3 to NaCl from the balanced equation. In this case, it is 1:1.
Step 3: Calculate the number of moles of NaCl:
moles of NaCl = volume of NaCl solution (in liters) ร concentration of NaCl (in moles per liter)
moles of NaCl = 47.1 mL รท 1000 mL/L ร 0.278 moles/L
Step 4: Based on the stoichiometry, the number of moles of AgNO3 required will be the same as the moles of NaCl.
Step 5: Calculate the volume of AgNO3 solution required:
volume of AgNO3 solution (in liters) = moles of AgNO3 รท concentration of AgNO3 (in moles per liter)
volume of AgNO3 solution = moles of NaCl รท 0.277 moles/L
Step 6: Convert the volume in liters to milliliters:
volume of AgNO3 solution = volume of AgNO3 solution ร 1000 mL/L
Step 7: Calculate the grams of AgCl formed:
moles of AgCl = moles of NaCl (since they have a 1:1 stoichiometric ratio)
mass of AgCl = moles of AgCl ร molar mass of AgCl
Now you can plug in the values and calculate the results.