Claus
This page lists questions and answers that were posted by visitors named Claus.
Questions
The following questions were asked by visitors named Claus.
Liquid Nitrogen tetroxide, N2O4(l), was used as a fuel in Apollo missions to the moon. In a closed container the gas N2O4(g) decomposes to nitrogen dioxide, NO2(g). The equilibrium constant,k, for this reaction is 0.87 at 55 degrees Celsius. A vessel fill...
17 years ago
Hi DrBob, you are an inspiration to my brother since he tells me you help so many people including himself with your generosity.Thank you!. My brother was wondering if you will be online later tonight since he needs help with three questions when he gets...
17 years ago
Keq = [0.25 - x] / [0.25 - x][2x] = [0.25 - ] / [0.25 - ][2()] = What numbers need to be substituted
17 years ago
AgCl <==> Ag^+ + Cl^- NaCl ==> Na^+ + Cl^- Ksp = (Ag^+)(Cl^-) = 1.8 x 10^-10 Let S = solubility of AgCl, then (Ag^+) = S (Cl^-) = S+0.01 Solve for S. Note: A similar problem to this post (0.1 M NaCl instead of 0.01 M NaCl) was on a couple of days ago; the...
17 years ago
Answers
The following answers were posted by visitors named Claus.
God bless you!:) He says he wants to become a doctor like you:P His screen name is MikeSo
17 years ago
Keq = [0.25 - x] / [0.25 - x][2x] = [0.25 - ] / [0.25 - ][2()] = What numbers need to be substituted?
17 years ago
I2 + Cl2 ==> 2ICl (Is that the equation?) initially: (I2) = 0.5/2.0 = ?? (Cl2) = 0.5/2.0 = ?? (ICl)= 0 change: (ICl) = +2x (I2) = -x (Cl2) = -x equilibrium: (ICl) = 0 + 2x = 2x (I2) = (0.5/2.0) - x = 0.25 - x (Cl2) = (0.5/2.0) - x = 0.25 - x Set up Keq, s...
17 years ago