Ask a New Question
Search
A vinegar sample was analyzed
Could someone help me with this question?
A vinegar sample was analyzed and found to be 5.88% acetic acid by volume. The density
1 answer
asked by
Tyler
1,419 views
A vinegar sample was analyzed and found to be 5.88% acetic acid by volume. The density of pure acetic acid is 1.049g/mL. What
1 answer
asked by
sara
2,114 views
12.5g mass of the vinegar sample and the density of vinegar is 1.05g/mL determine the volume of the vinegar sample in liters?
1 answer
asked by
Anonymous
882 views
1. Harry titrates vinegar with 0.952 M NaOH. The sample was 25.75 mL of vinegar, and it took 19.85 ml of 0.952 M NaOH to reach
1 answer
asked by
tori
552 views
I need help with how to do this!
-If a 7.0mL sample of vinegar was titrated to the stoichiometric equivalence point with 7.5mL of
1 answer
asked by
Debbie
2,135 views
A 30.84 cm3 volume of 0.128 M NaOH is required to reach the
phenolphthalein endpoint in the titration of a 5.441 g sample of
0 answers
asked by
Felix
389 views
Q1
In order to determine the concentration of acetic acid in a sample of vinegar, a student titrated a sample of vinegar with
1 answer
asked by
Brittany Rusk
748 views
assuming the vinegar solution has a density of 1.01 g/mL, calculate the percent by weight of actic acid (CH3CO2H) in your sample
1 answer
asked by
Wandy
1,256 views
Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 4.69 g sample of vinegar was neutralized by 32.97 mL of
2 answers
asked by
Chris
4,452 views
A 3.455 g sample of vinegar is titrated. It requires 16.83 mL of 0.2145 M NaOH to get to the phenolphthalein end point.
2 answers
asked by
ashlee
626 views