Asked by Chris
Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 4.69 g sample of vinegar was neutralized by 32.97 mL of 0.100 M NaOH. What is the percent by weight of acetic acid in the vinegar?
Answers
Answered by
DrBob222
CH3COOH + NaOH ==> CH3COONa + H2O
mols NaOH = M x L = ?
mols CH3COOH = mols NaOH (because of the 1:1 coefficients in the balanced equation.)
g CH3COOH = mols CH3COOH x molar mass CH3COOH.
Then % CH3COOH = (g CH3COOH/mass sample)*100 = ?
mols NaOH = M x L = ?
mols CH3COOH = mols NaOH (because of the 1:1 coefficients in the balanced equation.)
g CH3COOH = mols CH3COOH x molar mass CH3COOH.
Then % CH3COOH = (g CH3COOH/mass sample)*100 = ?
Answered by
Selton Sevo
4.22 percent
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