Asked by Samantha
Vinegar is 5% acetic acid. If the density of household vinegar is approximately 1.00 g/mL, how many grams of acetic acid are contained in 10.0 mL of vinegar?
So I started out with 10.0 mL of HC2H3O2 then multiplied by 1.00g/1mL. What do I do next? Is it done there?
So I started out with 10.0 mL of HC2H3O2 then multiplied by 1.00g/1mL. What do I do next? Is it done there?
Answers
Answered by
DrBob222
10 mL x 1.0 g/mL = 10 g is the mass of the 10 mL.
That is 5% acetic acid; therefore,
0.05 x 10 g = 0.5 g ia acetic acid. The remainder of 9.5 g is H2O.
That is 5% acetic acid; therefore,
0.05 x 10 g = 0.5 g ia acetic acid. The remainder of 9.5 g is H2O.
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