Question
Vinegar is 5% acetic acid. If the density of household vinegar is approximately 1.00 g/mL, how many grams of acetic acid are contained in 10.0 mL of vinegar?
So I started out with 10.0 mL of HC2H3O2 then multiplied by 1.00g/1mL. What do I do next? Is it done there?
So I started out with 10.0 mL of HC2H3O2 then multiplied by 1.00g/1mL. What do I do next? Is it done there?
Answers
10 mL x 1.0 g/mL = 10 g is the mass of the 10 mL.
That is 5% acetic acid; therefore,
0.05 x 10 g = 0.5 g ia acetic acid. The remainder of 9.5 g is H2O.
That is 5% acetic acid; therefore,
0.05 x 10 g = 0.5 g ia acetic acid. The remainder of 9.5 g is H2O.
Related Questions
Could you help me find some websites that can tell me what the ingredients are in vinegar.
http://e...
Vinegar is a 5.0% solution by weight of acetic acid in water. Given that the pH for vinegar is 2.41...
Calculate the mole fraction of acetic acid in vinegar, assuming that vinegar is 5.00% acetic acid(by...
assuming the vinegar solution has a density of 1.01 g/mL, calculate the percent by weight of actic a...