1. (sinx/cscx)+(cosx/secx)=1 2. (1/sinxcosx)-(cosx/sinx)=tanx 3.

Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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2. asked by Dave
3. 1,486 views
Prove the following identity:1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
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2. asked by Heather
3. 826 views
My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
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2. asked by Jon
3. 970 views
1. (sinx/cscx)+(cosx/secx)=12. (1/sinxcosx)-(cosx/sinx)=tanx 3. (1/1+cos s)=csc^2 s-csc s cot s 4.
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2. asked by Tom
3. 809 views
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1. 1 answer
2. asked by Anonymous
3. 1,122 views
1/tanx-secx+ 1/tanx+secx=-2tanxso this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
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2. asked by olivia
3. 1,375 views
Proving identity(sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)
1. 1 answer
2. asked by sh
3. 655 views
Which of the following are trigonometric identities?(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
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2. asked by Jill
3. 4,838 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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2. asked by shan
3. 1,018 views
I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equationProblem 1.
1. 2 answers
2. asked by Alycia
3. 746 views