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1. (sinx/cscx)+(cosx/secx)=1 2. (1/sinxcosx)-(cosx/sinx)=tanx 3.
Trigonometric Identities
Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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asked by
Dave
1,424 views
Prove the following identity:
1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
1 answer
asked by
Heather
765 views
My previous question:
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
2 answers
asked by
Jon
896 views
1. (sinx/cscx)+(cosx/secx)=1
2. (1/sinxcosx)-(cosx/sinx)=tanx 3. (1/1+cos s)=csc^2 s-csc s cot s 4.
1 answer
asked by
Tom
740 views
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
asked by
Anonymous
1,054 views
1/tanx-secx+ 1/tanx+secx=-2tanx
so this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
0 answers
asked by
olivia
1,308 views
Proving identity
(sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)
1 answer
asked by
sh
611 views
Which of the following are trigonometric identities?
(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
1 answer
asked by
Jill
4,768 views
tanx+secx=2cosx
(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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asked by
shan
958 views
I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equation
Problem 1.
2 answers
asked by
Alycia
696 views