1. (sinx/cscx)+(cosx/secx)=1 2. (1/sinxcosx)-(cosx/sinx)=tanx 3.

  1. Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
    1. answers icon 0 answers
    2. Dave asked by Dave
    3. views icon 1,424 views
  2. Prove the following identity:1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
    1. answers icon 1 answer
    2. Heather asked by Heather
    3. views icon 765 views
  3. My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
    1. answers icon 2 answers
    2. Jon asked by Jon
    3. views icon 896 views
  4. 1. (sinx/cscx)+(cosx/secx)=12. (1/sinxcosx)-(cosx/sinx)=tanx 3. (1/1+cos s)=csc^2 s-csc s cot s 4.
    1. answers icon 1 answer
    2. Tom asked by Tom
    3. views icon 740 views
  5. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 1,054 views
  6. 1/tanx-secx+ 1/tanx+secx=-2tanxso this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
    1. answers icon 0 answers
    2. olivia asked by olivia
    3. views icon 1,308 views
  7. Proving identity(sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)
    1. answers icon 1 answer
    2. sh asked by sh
    3. views icon 611 views
  8. Which of the following are trigonometric identities?(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
    1. answers icon 1 answer
    2. Jill asked by Jill
    3. views icon 4,768 views
  9. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
    1. answers icon 0 answers
    2. shan asked by shan
    3. views icon 958 views
  10. I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equationProblem 1.
    1. answers icon 2 answers
    2. Alycia asked by Alycia
    3. views icon 696 views