1/tanx-secx+ 1/tanx+secx=-2tanx

so this is what I did:
=tanx+secx+tanx-secx
=(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
=sinx/cosx+ sinx /cosx= -2tanxI

but I know this can't be correct because what I did doesn't end as a negatvie:( please help

Similar Questions

Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
1. 0 answers
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1. 1 answer
1. (sinx/cscx)+(cosx/secx)=12. (1/sinxcosx)-(cosx/sinx)=tanx 3. (1/1+cos s)=csc^2 s-csc s cot s 4.
1. 1 answer
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
1. 0 answers