Asked by Heather
Prove the following identity:
1/tanx + tanx = 1/sinxcosx
I can't seem to prove it. This is my work, I must've made a mistake somewhere:
Converted 1/tanx: 1/sinx/cosx + sinx/cosx = 1/sinxcosx
Simplified 1/sinx/cosx: cosx/sinx + sinx/cosx = 1/sinxcosx
Found common denominator and multiplied numerator: sinxcosx/sinxcosx + sinxcosx/sinxcosx = 1/sinxcosx
Simplified: 2sinxcosx/sinxcosx
Wouldn't that simplify to just sinxcosx, not 1/sinxcosx?
1/tanx + tanx = 1/sinxcosx
I can't seem to prove it. This is my work, I must've made a mistake somewhere:
Converted 1/tanx: 1/sinx/cosx + sinx/cosx = 1/sinxcosx
Simplified 1/sinx/cosx: cosx/sinx + sinx/cosx = 1/sinxcosx
Found common denominator and multiplied numerator: sinxcosx/sinxcosx + sinxcosx/sinxcosx = 1/sinxcosx
Simplified: 2sinxcosx/sinxcosx
Wouldn't that simplify to just sinxcosx, not 1/sinxcosx?
Answers
Answered by
bobpursley
cosx/sinx + sinx/cosx = 1/sinxcosx
common denominator: sinxcosx
(cos^2x+sin^2x)/sinxcosx
not it is proved, as the numberator is 1.
common denominator: sinxcosx
(cos^2x+sin^2x)/sinxcosx
not it is proved, as the numberator is 1.
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