Asked by Kyle
Prove this identity using the product-to-sum identity for sine:
sin^2 x=1-cos(2x)/2
sin^2 x=1-cos(2x)/2
Answers
Answered by
Damon
YOU MEAN
sin^2 x=[ 1-cos(2x) ] /2
or
2 sin^2 x = 1 - cos(2x)
cos 2 x = cos^2 x - sin^2 x
so
2 sin^2 x = 1 - cos^2 x + sin^2 x
sin^2 x = 1 - cos^2 x
or
sin^2 x + cos^2 x = 1
which is true
sin^2 x=[ 1-cos(2x) ] /2
or
2 sin^2 x = 1 - cos(2x)
cos 2 x = cos^2 x - sin^2 x
so
2 sin^2 x = 1 - cos^2 x + sin^2 x
sin^2 x = 1 - cos^2 x
or
sin^2 x + cos^2 x = 1
which is true
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