Asked by Anonymous
Prove the identity: cos^4(x)-sin^4(x)=1-2sin^2(x).with explanation
im confused on this one cause of the 4th power of the sine. does this mean that we put it in the calculator 4 times? and what exactly does it mean by prove the identity- does it mean like make sure both sides equal each other?
im confused on this one cause of the 4th power of the sine. does this mean that we put it in the calculator 4 times? and what exactly does it mean by prove the identity- does it mean like make sure both sides equal each other?
Answers
Answered by
Bosnian
cos ^ 4( x ) - sin ^ 4 ( x ) =
[ cos ^ 2 ( x ) ] ^ 2 - [ sin ^ 2 ( x ) ] ^ 2 =
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Remark:
a ^ 2 - b ^ 2 = ( a + b ) * ( a - b )
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= [ cos ^ 2 ( x ) + sin ^ 2 ( x ) ] *
[ cos ^ 2 ( x ) - sin ^ 2 ( x ) ] =
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Remark:
cos ^ 2 ( x ) + sin ^ 2 ( x ) = 1
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= 1 * [ cos ^ 2 ( x ) - sin ^ 2 ( x ) ] =
cos ^ 2 ( x ) - sin ^ 2 ( x ) =
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Remark:
cos ^ 2 ( x ) = 1 - sin ^ 2 ( x )
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= 1 - sin ^ 2 ( x ) - sin ^ 2 ( x ) =
1 - 2 sin ^ 2 ( x )
[ cos ^ 2 ( x ) ] ^ 2 - [ sin ^ 2 ( x ) ] ^ 2 =
______________________________________
Remark:
a ^ 2 - b ^ 2 = ( a + b ) * ( a - b )
______________________________________
= [ cos ^ 2 ( x ) + sin ^ 2 ( x ) ] *
[ cos ^ 2 ( x ) - sin ^ 2 ( x ) ] =
______________________________________
Remark:
cos ^ 2 ( x ) + sin ^ 2 ( x ) = 1
______________________________________
= 1 * [ cos ^ 2 ( x ) - sin ^ 2 ( x ) ] =
cos ^ 2 ( x ) - sin ^ 2 ( x ) =
______________________________________
Remark:
cos ^ 2 ( x ) = 1 - sin ^ 2 ( x )
______________________________________
= 1 - sin ^ 2 ( x ) - sin ^ 2 ( x ) =
1 - 2 sin ^ 2 ( x )
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