The slope of the tangent line to a curve is given by f'(x)=4x^2 + 7x -9. If the point (0,6) is on the curve, find an equation of the curve.
2 answers
y-y1=m(x-x1)
if
f'(x)=4x^2 + 7x -9
then
f(x) = y = (4/3) x^3 + (7/2)x^2 - 9 x + constant
use point to get constant
6 = 0 + constant
f'(x)=4x^2 + 7x -9
then
f(x) = y = (4/3) x^3 + (7/2)x^2 - 9 x + constant
use point to get constant
6 = 0 + constant
1 answer