Asked by Mary
The slope of the tangent line to the graph y= x^3/x -x at the point (1, -2/3)
I keep getting undefined as a answer but.. I feel like I might be doing something wrong because I feel like that is not the answer, can you help me please?
I keep getting undefined as a answer but.. I feel like I might be doing something wrong because I feel like that is not the answer, can you help me please?
Answers
Answered by
Reiny
could be the way you typed your equation.
The way you typed it, why not just simplify x^3/x to x^2 ?
That is why I am suspicious about the way it was typed.
Did you mean y = x^(3/x) - x ?
The way you typed it, why not just simplify x^3/x to x^2 ?
That is why I am suspicious about the way it was typed.
Did you mean y = x^(3/x) - x ?
Answered by
Rachel
The equation is y= x cubed over x minus x
so;
y= x^3 / x -x
Sorry for being confusingg
so;
y= x^3 / x -x
Sorry for being confusingg
Answered by
Reiny
y = x^3/x- x would reduce to
y = x^2 - x
and (1,-2/3) would NOT lie on this curve.
So there is something wrong with the way you typed it
Use brackets to establish the correct form
Otherwise this question is bogus.
y = x^2 - x
and (1,-2/3) would NOT lie on this curve.
So there is something wrong with the way you typed it
Use brackets to establish the correct form
Otherwise this question is bogus.
Answered by
Rachel
Okay I sure will! Thanks
Answered by
Mary
Hmmm you know what, I think this problem is an error. Maybe that's why I could not figure it outt?