Asked by Arnold

The slope of the tangent line to the graph y= x^3/3-x at the point (1, -2/3)

So I plugged this into y= and I found the (1,-2/3) point but I don't know what to do next, can you help?

Answers

Answered by Steve
the tangent line has the same slope as the curve at the point of tangency. The slope at any x is

y' = x^2-1
So, y'(1) = 0

Now you have a point and a slope, so the line is

y + 2/3 = 0(x-1)
or,
y = -2/3

See the graphs at

http://www.wolframalpha.com/input/?i=plot+y%3D+x^3%2F3-x%2C+y%3D-2%2F3
Answered by Anonymous
The answer is 0

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