Asked by Rudy
the slope of the line tangent to the curve y=(tanx/cosx) at x=(pi/3) is?
a)-8
b)2√3
c)3√2
d)8
e)14
a)-8
b)2√3
c)3√2
d)8
e)14
Answers
Answered by
Steve
y'(x) = (sec^2*cos + tan*sin)/cos^2
y'(pi/3) = (4*(1/2) + √3 * √3/2)/(1/4) = 14
y'(pi/3) = (4*(1/2) + √3 * √3/2)/(1/4) = 14
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