the slope of the line tangent to the curve y=(tanx/cosx) at x=(pi/3) is?

Question

a)-8
b)2√3
c)3√2
d)8
e)14

Answer 1

y'(x) = (sec^2*cos + tan*sin)/cos^2
y'(pi/3) = (4*(1/2) + √3 * √3/2)/(1/4) = 14