a. To prove that the 8-ball at point I is equidistant from the hole at point F and the hole at point C, we can use the property of a perpendicular bisector. Since line segment GH is the perpendicular bisector of segment FC, it means that any point on line GH, including point I, is the same distance from both endpoints F and C. Therefore, the distance from point I to point F is equal to the distance from point I to point C, proving that the 8-ball is equidistant from both holes.
b. Another point that would be equidistant from points F and C is point J, where line segment GH intersects line segment FC. We know this because point J lies on the perpendicular bisector of FC, which means it is also equally distant from both F and C, just like point I. This property of perpendicular bisectors tells us that any point on it will always have the same distance to the endpoints of the segment it bisects.