a. Proof that the 8-ball at point I is equidistant from points F and C:
Paragraph Proof: The line segment GH is the perpendicular bisector of segment FC. By the definition of a perpendicular bisector, it divides segment FC into two equal halves and is perpendicular to it at the midpoint J. Since point I lies on the perpendicular bisector GH, it means that the distances from I to points F and C must be equal. Therefore, we can conclude that the 8-ball located at I is equidistant from both holes F and C.
Two-Column Proof:
| Statement | Reason | |-----------|--------| | 1. GH is the perpendicular bisector of FC. | Given | | 2. J is the midpoint of FC. | Definition of a perpendicular bisector | | 3. Point I is located on GH. | Given | | 4. By definition of a perpendicular bisector, any point on GH is equidistant from F and C. | Definition of a perpendicular bisector | | 5. Thus, distance IF = distance IC. | From the definition in Statement 4 |
Consequently, Mark can confidently hit the ball towards either hole, as it is equally distant from both.
b. Another point in the diagram that would be equidistant from points F and C is point J, the midpoint of segment FC.
Explanation: Since J is the midpoint of line segment FC, by definition, it is located exactly halfway between points F and C. Thus, the distances FJ and CJ are equal, making point J equidistant from points F and C. This characteristic of midpoints is a fundamental property in geometry, confirming that segment lengths from F to J and from C to J are the same.