Part A: Proof that point I is equidistant from points F and C
Proof:
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Statement: Line segment GH is the perpendicular bisector of line segment FC.
- Reason: By definition of a perpendicular bisector, it is a line that is perpendicular to a segment at its midpoint.
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Statement: Point J is the midpoint of segment FC.
- Reason: Since GH is the perpendicular bisector of FC, it intersects FC at its midpoint.
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Statement: Point I is located on the perpendicular bisector GH.
- Reason: It is given in the problem that the 8-ball is at point I, which lies on line segment GH.
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Statement: According to the properties of perpendicular bisectors, any point on the perpendicular bisector of a segment is equidistant from the endpoints of that segment.
- Reason: This is a geometric property of perpendicular bisectors.
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Conclusion: Since point I lies on the perpendicular bisector GH of segment FC, it follows that the distances from point I to points F and C are equal.
- Final Statement: Therefore, the 8-ball at point I is equidistant from both holes at points F and C.
Part B: Another Point Equidistant from F and C
Another point in the diagram that would also be equidistant from points F and C is point J, which is the intersection point of line segment GH (the perpendicular bisector) with line segment FC.
Explanation: Since point J is the midpoint of segment FC (as established in part A), and by the properties of midpoints and perpendicular bisectors, J is equidistant from points F and C. Thus, the distances from point J to points F and C are equal, just like point I, confirming that J is also equidistant from points F and C.