To address your request, I will provide a proof regarding the position of the 8-ball and identify another point that is equidistant from points F and C.
Part A: Proof that point I is equidistant from points F and C
Let's use a paragraph proof:
Paragraph Proof:
- Definition of Perpendicular Bisector: A perpendicular bisector of a line segment is a line that is perpendicular to the segment at its midpoint and divides the segment into two equal parts.
- Given: Line segment \(GH\) is the perpendicular bisector of line segment \(FC\). By definition, this means that \(J\), the point where \(GH\) intersects \(FC\), is the midpoint of segment \(FC\).
- Location of Point I: Point \(I\) is located on the perpendicular bisector \(GH\).
- Properties of Perpendicular Bisector: Since point \(I\) lies on the perpendicular bisector of segment \(FC\), it is equidistant from both endpoints \(F\) and \(C\).
- Conclusion: Therefore, the distance from point \(I\) to point \(F\) is equal to the distance from point \(I\) to point \(C\) (\(IF = IC\)). As a result, the 8-ball at point \(I\) is equidistant from both holes at points \(F\) and \(C\).
Part B: Identify another point equidistant from F and C
Another point that is also equidistant from points \(F\) and \(C\) is point \(J\).
Explanation:
- Position of Point J: Point \(J\) is defined as the intersection of the line segment \(GH\) (the perpendicular bisector) and the segment \(FC\).
- Definition of Midpoint: By the properties of a perpendicular bisector, \(J\) is the midpoint of segment \(FC\).
- Equidistant Property: Since \(J\) is the midpoint, it is equidistant from both points \(F\) and \(C\) (\(JF = JC\)), satisfying the condition of having equal distances to both points.
Thus, point \(J\) is another point that is equidistant from points \(F\) and \(C\).