a. Paragraph Proof
To prove that the 8-ball at point I is equidistant from the holes at points F and C, we can use the properties of the perpendicular bisector. By definition, a perpendicular bisector of a segment divides the segment into two equal halves and is perpendicular to that segment. In this case, segment FC is bisected by line segment GH at point J, meaning that:
- Point J is the midpoint of segment FC.
- Therefore, segments FJ and JC are equal in length (FJ = JC).
- Since point I lies on the perpendicular bisector GH, any point on a perpendicular bisector is equidistant to the endpoints of the segment it bisects.
- Thus, the distance from point I to point F is equal to the distance from point I to point C (IF = IC).
Hence, we can conclude that the 8-ball is equidistant from the holes at points F and C.
b. Another Equidistant Point
Another point in the diagram that would also be equidistant from points F and C is point J, the point of intersection of the perpendicular bisector GH and segment FC.
This is because:
- As stated earlier, J is the midpoint of FC, which means that it is located exactly halfway between F and C.
- By the properties of a bisector, we know that the distances from the midpoint to each endpoint are equal (FJ = JC).
- Therefore, point J, like point I, is also equidistant from points F and C.
Marks can use this property of midpoints and perpendicular bisectors to understand that there are indeed multiple points, such as I and J, that are equidistant from F and C.