Part a: Proof that the 8-ball is equidistant from holes F and C
Paragraph Proof:
To prove that the point I (where the 8-ball is located) is equidistant from points F and C (the holes), we can use the property of perpendicular bisectors. Since GH is the perpendicular bisector of segment FC, by definition, any point that lies on the perpendicular bisector is equidistant from the endpoints of the segment it bisects. Therefore, since point I lies on perpendicular bisector GH, we conclude that the distance from point I to point F is equal to the distance from point I to point C. Thus, we can write:
- GH is the perpendicular bisector of segment FC.
- By definition of a perpendicular bisector, any point on it is equidistant from the endpoints of the segment it bisects.
- Since point I is on the perpendicular bisector GH, it is equidistant from points F and C.
- Therefore, the distance IF (distance from point I to point F) is equal to the distance IC (distance from point I to point C): IF = IC.
Hence, Mark can conclude that the 8-ball at point I is equidistant from holes F and C.
Part b: Another point equidistant from points F and C
Another point that would also be equidistant from points F and C is the midpoint of segment FC.
Explanation:
The midpoint of a segment is defined as the point that is exactly halfway between the two endpoints of that segment. In this case, if we let the midpoint of segment FC be denoted as point M, then by the definition of a midpoint, point M is at equal distance from both endpoints F and C. Therefore, the distances FM and CM are equal, symbolically written as FM = CM.
Since the midpoint M lies directly on the segment FC, it can also be observed that if M is on GH (the perpendicular bisector of FC), which it must be, then it further reinforces the concept that any point on the perpendicular bisector (including M) remains equidistant from F and C.