Ask a New Question

Asked by ALEX

using rational functions solve (x+5)/(x-3)= (2x+7)/(x)

thank you
12 years ago

Answers

Answered by Steve
as with all fractions , cross-multiply to get rid of them:

(x+5)(x) = (2x+7)(x-3) assuming x≠0,3
x^2+5x = 2x^2+x-21
x^2-4x-21 = 0
(x-7)(x+3) = 0
x = -3,7

check:
(-3+5)/(-3-3) = -1/3 = (-6+7)/(-3)
(7+5)/(7-3) = 3 = (14+7)/7
12 years ago

Related Questions

1. Some rational functions have asymptotes, others have holes, and some have both. Explain how you c... Rational Functions does the following function have a hole or a vertical asymptote or both? how d... Rational Functions y = (x^2+7x-4)/(x-2) Since the degrees of both the numerator and denominato... Using rational functions solve x+5(numerator) x-3 (denominator) = 2x+7 (numerator) x(demominator) Using rational functions solve 7+ 1(numerator) x (denominator) = 1 (numerator) x-2(demominator) Using rational functions solve 3(numerator) 2x-4 (denominator) < (with a "-" underneath) 4 (numera... Using rational functions solve (7+ 1)/x = 1/(x-2) Using rational functions solve 7+ (1)/x = 1/(x-2) thank you All rational functions can be expressed as f(x) = p(x)/q(x), where p and q are __________ functions...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use