Question

Using rational functions solve
3(numerator) 2x-4 (denominator) < (with a "-" underneath) 4 (numerator) x-2(demominator)

Answer 1

do you mean?

3/(2x-4) ≤ 4/(x-2) ??

I will asssume that

3/(2x-4) ≤ 8/(2x-4)
multiply both sides by 2x-4

case1: 2x-4 > 0
then 3 ≤ 8 , which is true
so it is true for all values of x ≥ 2

case2: 2x-4 < 0
3 ≥ 8 , which is false, so no value of x makes that possible

then x > 2

(in this forum we use / to show division and brackets to avoid confusion as to numerator and denominator)