Asked by Anonymous
For the functions below, solve for f(g(h(-1))).
f(x)=(x-1)^2
g(x)=2x^2+3x-1
h(x)=(x+3)
f(x)=(x-1)^2
g(x)=2x^2+3x-1
h(x)=(x+3)
Answers
Answered by
Steve
h(-1) = 2
g(2) = 13
f(13) = 144
or
f(g(h)) = (g(h)-1)^2
= ((2h^2+3h-1)-1)^2
= (2h^2+3h-2)^2
= (2(x+3)^2+3(x+3)-2)^2
= 4x^4+60x^3+325x^2+750x+625
= 4-60+325-750+625
= 144
I think the first way is easier!
g(2) = 13
f(13) = 144
or
f(g(h)) = (g(h)-1)^2
= ((2h^2+3h-1)-1)^2
= (2h^2+3h-2)^2
= (2(x+3)^2+3(x+3)-2)^2
= 4x^4+60x^3+325x^2+750x+625
= 4-60+325-750+625
= 144
I think the first way is easier!
Answered by
Anonymous please help
I don't get how you got that answer.
how did f(x)=(x-1)^2 become f(13) = 144
and the second way I don't get where that answer came from? can you please explain.
how did f(x)=(x-1)^2 become f(13) = 144
and the second way I don't get where that answer came from? can you please explain.
Answered by
Steve
f(x) = (x-1)^2
so
f(13) = (13-1)^2 = 12^2 = 144
so
f(13) = (13-1)^2 = 12^2 = 144
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.