Asked by Jenny
A 50.0g ball of clay traveling east at 3.00 m/s collides and sticks
together with a 50.0g ball of clay traveling north at 3.50m/s.
What is the speed and direction of the resulting ball of clay?
together with a 50.0g ball of clay traveling north at 3.50m/s.
What is the speed and direction of the resulting ball of clay?
Answers
Answered by
Damon
initial east momentum = 150
initial north momentum = 175
final mass = 100 g
initial east momentum = final
so
final east = 150 = 100 u
u = 1.5
initial north momentum = final
so
final north = 175 = 100 v
v = 1.75
speed = sqrt (1.5^2+1.75^2)
tan angle n of e = 1.75/1.5
initial north momentum = 175
final mass = 100 g
initial east momentum = final
so
final east = 150 = 100 u
u = 1.5
initial north momentum = final
so
final north = 175 = 100 v
v = 1.75
speed = sqrt (1.5^2+1.75^2)
tan angle n of e = 1.75/1.5
Answered by
iojoi
I love you
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.