Asked by Angelica
A 24g ball of clay traveling east at 3.3m/s collides with a 33g ball of clay traveling north at 2.4m/s .
1a)What is the movement direction of the resulting 57g blob of clay?
1b)What is the speed of the resulting 57g blob of clay?
1a)What is the movement direction of the resulting 57g blob of clay?
1b)What is the speed of the resulting 57g blob of clay?
Answers
Answered by
Henry
X = M1*V1 = 24*3.3 = 79.2
Y = M2*V2 = 33*2.4 = 79.2
1a. Tan A = Y/X = 79.2/79.2 = 1.00
A = 45o = Direction.
1b. Momentum = X/Cos A = 79.2/Cos45 = 112
(M1+M2)*V = 112[45o]
(33+24)V = 112[45]
V = 1.96 m/s.[45o]
Y = M2*V2 = 33*2.4 = 79.2
1a. Tan A = Y/X = 79.2/79.2 = 1.00
A = 45o = Direction.
1b. Momentum = X/Cos A = 79.2/Cos45 = 112
(M1+M2)*V = 112[45o]
(33+24)V = 112[45]
V = 1.96 m/s.[45o]
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