Asked by Sandra
A 50 g ball of clay traveling east at 3.5 m/s collides and sticks together with a 50 g ball of clay traveling north at 2.0 m/s. What is the speed of the resulting ball of clay?
Answers
Answered by
Kifle Zanba
((m1)(v1))i+((m2)(v2))i =(m1+m2)Vf
[(0.05kg)(0)+(0.05kg)(2.0m/s)]
/[(0.05kg+0.05kg)]=1.0 m/s .........(east)
[(0.05kg)(3.5m/s)+(0.05kg)(0m/s)]
/[0.05kg+0.05kg)]= 17 m/s............(north)
(1)^2+(17)^2 = Vf^2
Vf=Sqrt[(1^2)+(17^2)]
Vf= 17.6 m/s
[(0.05kg)(0)+(0.05kg)(2.0m/s)]
/[(0.05kg+0.05kg)]=1.0 m/s .........(east)
[(0.05kg)(3.5m/s)+(0.05kg)(0m/s)]
/[0.05kg+0.05kg)]= 17 m/s............(north)
(1)^2+(17)^2 = Vf^2
Vf=Sqrt[(1^2)+(17^2)]
Vf= 17.6 m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.