Question
20 g ball of clay traveling east at 3.0 m/s collides with a 30 g ball of clay traveling north at 2.0 m/s. What are the speed and the direction of the resulting 50 g ball of clay?
Answers
momentum east = 20*3 = 60
momentum north = 30 * 2 = 60
momentum east = 50*Ve = 60
momentum north = 50*Vn = 60
Ve = 6/5
Vn = 6/5
angle = 45
speed = (6/5) sqrt 2
momentum north = 30 * 2 = 60
momentum east = 50*Ve = 60
momentum north = 50*Vn = 60
Ve = 6/5
Vn = 6/5
angle = 45
speed = (6/5) sqrt 2
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