Asked by Joy
if the mole fractionof sulfuric acid (H2SO4) in an aqueous solitioin is 0.325, what is the percent by mass of H2SO4?
Answers
Answered by
DrBob222
XH2SO4 = 0.325
XH2O = 1-0.325 = 0.675
XH2SO4 = mols H2SO4/total mols.
1 mol H2SO4 = 98 grams.
0.325 mol H2SO4 = 0.3 x 98 = 31.85g H2SO4 in 0.675 x 18 = 12.15 g H2O
Total mass = 12.15 + 31.85 = 44.0 g
% H2SO4 = (g H2SO4/total g)*100 =
(31.85/44)*100 = ?
XH2O = 1-0.325 = 0.675
XH2SO4 = mols H2SO4/total mols.
1 mol H2SO4 = 98 grams.
0.325 mol H2SO4 = 0.3 x 98 = 31.85g H2SO4 in 0.675 x 18 = 12.15 g H2O
Total mass = 12.15 + 31.85 = 44.0 g
% H2SO4 = (g H2SO4/total g)*100 =
(31.85/44)*100 = ?
Answered by
Boomie
Actually, I have the same question in the book but i didn't know how to solve it, so I was searching and I found this website. Thank you very much and BYE
Answered by
Sarah
31%
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.