Asked by Maddy
If 25.0 cm3 of 0.50M sulfuric acid reacted with exactly 12.5 cm3 of sodium hydroxide, calculate the concentration of the alkali.
I first balanced the chemical equation between sulfuric acid and sodium hydroxide.
H2SO4 + 2NaOH --> 2H2O + Na2SO4
I converted the volume of sulfuric acid to litres then to mols. I multiplied by the mol ratio to get the moles of NaOH which was .025 mols then divided by the volume of the base to get 2M NaOH. Is this correct?
I first balanced the chemical equation between sulfuric acid and sodium hydroxide.
H2SO4 + 2NaOH --> 2H2O + Na2SO4
I converted the volume of sulfuric acid to litres then to mols. I multiplied by the mol ratio to get the moles of NaOH which was .025 mols then divided by the volume of the base to get 2M NaOH. Is this correct?
Answers
Answered by
DrBob222
yes
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.